Writing a function that creates a list and prints elements

Question

I tried creating a list and for loop to print elements.
#python

I was told that the function below, doesn’t create the list, it is using a hard-coded list instead. How can I fix it?

def list_iterate():
list1 = ["I", "Like", "Eating", "Banana", "Bread"]

for element in list1:
print(element)

list_iterate()

Answer 1

Let's say you have an input stored in a variable (variable "a" for example)
You want the function to create a list, then the function shall have one argument
def my_List(x):
x = list(x)
for i in x:
return i

print(my_List(a))

I hope I could help

Answer 2

okay

def my_List(x) :
return [x]

Answer 3

Ali Abdelhady print(i) won't return anything either, it will just print.

This whole post is unclear, we're still waiting for the original poster to answer.

Answer 4

Ali Abdelhady your function is wrong, it would stop in the first iteration of the loop.

Answer 5

Ali Abdelhady because the return statement will immediatly stop the function. In this case, the function will only return the first element of the list.

Answer 6

hey... seems u put already some brain in it.
Please hack the code in SL ib coding section and post the link.
Doesnt matter if it is not running.

Answer 7

Creates what list ? Your question is unclear, what do you mean by "Create list" exactly ?

Answer 8

def makeList() :
l = [1,2,3]
return l

Answer 9

Aymane Boukrouh thanks for the reply but can you tell me why?

Answer 10

https://code.sololearn.com/cQoO3u6eux44/?ref=app
Check if this is related to your question

Answer 11

Aymane Boukrouh so, I guess it should be print(i) instead?