Can somebody tell me why the output of this code is False ❓

Question

https://code.sololearn.com/cmT2EvyiaEL4/?ref=app

Answer 1

The is operator compares the identity of two objects.
x is y only when x and y refer to the same object.

x = [0,0,0]
y = x
print(x is y)

Use the id() function to check the identity of objects. If id(x) and id(y) are the same, then (x is y) is true.

https://docs.python.org/2/library/functions.html#id

Also compare '==' vs 'is'.

https://www.sololearn.com/Discuss/1122173/

Answer 2

What do you mean by saying " Why y[0][0] = 1 is different from z[0][0] = 1"? Can you give a bit more details?

Answer 3

Even if the code was like this

y=[[0,0,0],[0,0,0],[0,0,0]]
z=[[0,0,0],[0,0,0],[0,0,0]]
print(y is z)

it will still print false, this is not the correct usage for "is"
Use ==

Answer 4

Why y[0][0] =1 is different from z[0][0] =1 ❓