arithmetic operator Java

Question

Can anybody help me,
I have and assignment from my teacher
How to code x = 7*6+5/3 with the same order, and the output must be 19?

Answer 1

You have started to study the Java tutorial.

Have you tried to solve it?

Please show us your attempt!

Answer 2

HonFu Thank you so much for the answer!

i have tried it.

1st attempt :
I wrote x = 7*6+5/3, the output is 43

2nd attempt :
x = 7*(6+5)/3, the output is 25

3rd attempt :
x = 7*(6+5/3), the output is 49

4th attempt :
x = (7*6+5)/3, the output is 15

5th attempt :
x = 7*((6+5)/3), the output is 21

Answer 3

Ome Are your teacher sure about question is correct?
Is there missing anything?

Answer 4

Ome
I think, If it 15 not 5, among all possible cases.. Then,
(7*6+15)/3=19
Rest all you already tried..
And
you're welcome..

Answer 5

Jayakrishna Thank you for the answer! I don't know. Tbh, i kind of doubting her. I will ask her again then.

Answer 6

Jayakrishna Thank you so much for the answer!