I wants to count total ( 1 ) number present in the given length. This program is only from 0 to 100. But I wants upto 10000.

Question

#include <stdio.h>

int main()
{
int i,j,k,d,count=0,flag=0,flag1=0,a,count1=0,sum,b;

scanf("%d",&a);
printf("enter your length:%d",a);

for(i=1;i<=a;i++)
{
j=i/10;
if(j==1)
{
count++;
}
k=i%10;
if(k==1)
{
flag++;
}
if(i==100)
{
flag1++;
}
while(i > 100 && i < 999)
{
b=i%100;
if(b==1)
{
count1++;
}
i=i/100;
}
}
sum =count+flag+flag1+count1;
printf("\n 1 is present %d times.",sum);

return 0;
}

Answer 1

Plz give me some idea

Answer 2

Can you explain with an example?

Answer 3

You can do it in a much simpler way if I understand what you want to do correctly:

while (a != 0) {
if (a % 10 == 1) {
count++;
}

a = a / 10;
}

Answer 4

If you want through example then open my profile and see the program of (number ). You will get idea but in this program only upto 100 number 1 will count , I want upto 10000.