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Why line 3 has no effect on list b ?
a = [1,[2,3]] b = a[:] a[0] = 3 a[1][1] = 5 print(b) Output is [1, [2,5]]. I was expecting it to print [3,[2,5]]
2 ответов
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b is a genuine copy of a, so it has its own elements.
The list inside b however is a reference to the same list that's in a, so if you manipulate it directly, it changes in both lists (because it's actually one object).
As it happens, just yesterday I wrote a little something about how all of that works. Happy if you take a look. 🙂
https://code.sololearn.com/c89ejW97QsTN/?ref=app
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HonFu Great tutorial. It is interesting & informative.