What's wrong with it?

Question

Can't catch mistake (jungle camping code coach)

https://code.sololearn.com/cuIE6fk0MHHZ/?ref=app

Answer 1

Look it works.
Just replace i with x in the if else and don't convert your input to string explicitly...

x=input().split(" ")
animals=[]
for i in x:
print(i)
if "Grr" in i:
animals.append("Lion")
elif "Rawr" in i:
animals.append("Tiger")
elif "Ssss" in i:
animals.append("Snake")
elif "Chrip" in i:
animals.append("Bird")
animals_j=" ".join(animals)
print(animals_j)

Answer 2

Dananan Bananan andriy kan

Tiger not Tigger
Chirp not Chrip

Now the code should work.

Answer 3

Tiger not Tigger ;)

Answer 4

I don't know what you expected from your code. I just made it correct.

I commented out input() function and set some value to x
It outputs the result:
[EDITED]: I uncommented the second line with input() function. So you can try it

https://code.sololearn.com/cy4Cj8ZV9vSP

Answer 5

Here's a short one
https://code.sololearn.com/cJhmNLBixswO

Answer 6

x=input().split(" ")
animals=[]
for i in x:
if "Grr" == i:
animals.append("Lion")
elif "Rawr" == i:
animals.append("Tiger")
elif "Ssss" == i:
animals.append("Snake")
elif "Chirp" == i:
animals.append("Bird")
else:
continue
animals_j=" ".join(animals)
print(animals_j)

Answer 7

s=input("")
n=s.split(' ')
for i in n:
if i=='Grr':
print("Lion",end=" ")
elif i=='Rawr':
print("Tiger",end=" ")
elif i=="Ssss":
print("Snake",end=" ")
elif i=="Chirp":
print("Bird",end=" ")

you can try this also...no need to create another list

Answer 8

Sorry, I can't understand you.
Did you try the code in code playground that I've posted?
https://code.sololearn.com/cy4Cj8ZV9vSP

I replace input with the string:
"Rawr Chirp Ssss"
Output is:
Tiger Bird Snake

If you want to use user input just uncomment the line #2

Answer 9

s=input().split()
for y in s:
if(y=="Grr"):
print("Lion",end=' ')
elif(y=="Rawr"):
print("Tiger",end=' ')
elif(y=="Ssss"):
print("Snake",end=' ')
else:
print("Bird",end=' ')

I done it like this

Answer 10

Petro Skulsky, please do not spam.

Answer 11

because default represents else in switch case ( if you know if .. else ) when no condition is true it goes to else
the same with switch
here at the example you have 3 different cases and you switch x value
if x == 1 (first case) it will print x value only without any addition
if x == 2 (second case) it will print x value and add 2 to it so the result would be 3 + 2 = 5
will print 5
if x value not equal to 1 or 2 it will go to the default and add 5 to x value so the result would be 8

i hope you understand
gerard

Answer 12

С этого и нужно было начинать)
как указал(а) Denise Roßberg у тебя ошибка в слове Tiger.

as Denise Roßberg pointed out, you have a mistake in the word Tiger.

Answer 13

Try this
a=input()
lst=[]
sa=a.split()
for i in sa:
if i=='Grr':
lst.append('Lion')
elif i=='Rawr':
lst.append('Tiger')
elif i=='Ssss':
lst.append('Snake')
elif i=='Chirp':
lst.append('Bird')
result=' '.join(lst)
print(result)

Answer 14

You need to print "Chirp" instead of "Chrip" and "Tiger" instead of "Tigger"

Answer 15

I tried this as well but it results in no output

Answer 16

https://www.sololearn.com/coach/45?ref=app
It's from this code coach and for me it still doesn't work

Answer 17

I've solved it with end parameter but couldn't solve it with append function

Answer 18

Я вводил этот код в jungle camping code coach, 3ий и 5ый тест не исполняются, не получается найти ошибку

Answer 19

After I've corrected tiGer mistake the 3rd test in jungle camping does not execute

Answer 20

Thank you all! Now it works!