Unindent does not match any outer indentation level?

Question

Hey developers

I am a beginner in python and I'm facing this error in my code for creating the basic calculator.

Code:

while True:
print('Options:')
print('Enter add to add two numbers')
print('Enter minus to subtract two numbers')
print('Enter multiply to multiply two numbers')
print('Enter divide to divide two numbers')
print('Enter quit to exit the calculator')
user_input = input(":")

if user_input == "quit":
break
elif user_input == 'add':
num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))
result = str(num1 + num2)
print('THE ANSWER IS' + result)

elif user_input == 'minus':
num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))
result = str(num1 - num2)
print('THE ANSWER IS' + result)

elif user_input == 'multiply':
num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))
result = str(num1 * num2)
print('THE ANSWER IS' + result)

elif user_input == 'divide':
num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))
result = str(num1 / num2)
print('THE ANSWER IS' + result)

else:
print("ERROR 404")

print("Thank you for using eCalc")

what does this mean?

Thanks, if you answered

Answer 1

If u need the program let the user to continuously enter the 3 values , u should use (while except )expression but it is not work at this App

Answer 2

Mubashir M I believe what you need is 'revision' go through python course of Sololearn again and this will help too:
https://code.sololearn.com/cT5BRIbkia21/?ref=app

Answer 3

Show this code will do what u need num1=float(input("plz enter the first number : "))
num2=float(input("plz enter the second number : "))
sign=input("plz enter your sign : ")

if sign =="+":
sum=num1+num2
print("the sum is {}".format(sum))
elif sign=="-":
sub=num1-num2
print("the sub is {}".format(sub))
elif sign=="*":
mul=num1*num2
print(" the multiplication is {}".format(mul))
elif sign=="/":
if num2 ==0:
print("can't divided by zero'")
else:
div=num1/num2
print("num1/num2={}".format(div))

Answer 4

Indentation defines a code block. Code within a while loop is not surrounded with brackets, it just continues the same indentation. So:

while True:
#this is inside the 'while' block
#so is this.
#this too.
#This is not because the indentation is back to normal.

Your code starts:
while True:
print('Options') #This is within 'while' block
print('Enter ...') #This is no longer within the block because there's no indentation.

Everything after this is, of course, also not within the 'while' block, so your 'break' statement is not within a 'for' or 'while' loop, so there's nothing for it to break out from.

Answer 5

Your code arrangements is wrong

Answer 6

if user_input == "quit":
break
elif user_input == 'add': <-- This is your problem line!

The elif line should start level with the if line.

if user_input == "quit":
break
elif user_input == 'add':
#code block starting with indent.
elif...:
#more code
else:
#more code

Continue like this.

Answer 7

Thank you for the answers

Answer 8

Hey guys

I tried again and now its saying 'break' outside loop
What does that mean

Answer 9

Sorry if I'm firing a lot of questions in one post

Answer 10

here's the code now:

while True:
print('Options:')
print('Enter add to add two numbers')
print('Enter minus to subtract two numbers')
print('Enter multiply to multiply two numbers')
print('Enter divide to divide two numbers')
print('Enter quit to exit the calculator')
user_input = input(":")

if user_input == "quit":
break

elif user_input == 'add':
num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))
result = str(num1 + num2)
print('THE ANSWER IS' + result)

elif user_input == 'minus':
num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))
result = str(num1 - num2)
print('THE ANSWER IS' + result)

elif user_input == 'multiply':
num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))
result = str(num1 * num2)
print('THE ANSWER IS' + result)

elif user_input == 'divide':
num1 = float(input('Enter a number'))
num2 = float(input('Enter another number'))
result = str(num1 / num2)
print('THE ANSWER IS' + result)

else:
print("ERROR 404")

print("Thank you for using eCalc")

Answer 11

I have created my calculator: eCalc. Thank you for helping me out.