Can anyone say why the output differs in the following 2 codes ?

Question

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Code #1 :
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import re
pattern = r"(.*) \1"
match = re.match(pattern, "word word")
if match:
print ("Match 1")
match = re.match(pattern, "?! ?!")
if match:
print ("Match 2")
match = re.match(pattern, "abc cde")
if match:
print ("Match 3")
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Code #2 :
-------------------
import re
pattern = r"(.*)"
match = re.match(pattern, "word word")
if match:
print ("Match 1")
match = re.match(pattern, "?! ?!")
if match:
print ("Match 2")
match = re.match(pattern, "abc cde")
if match:
print ("Match 3")

The first code gives the output...
Match 1
Match 2
Whereas the second code gives the output...
Match 1
Match 2
Match 3

Why ?

Answer 1

The pattern "(.*) \1" means that it needs to match the group (.*) (which is any number of anything) but it then has to be followed by a space (as there is a space in the pattern) and then the same group again (which the '\1' requires).

The third string is "abc cde" but because it's not the same two things separated by a space, it does not match.