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C Code explanation
This question was in C challenge What will be the output of the following code: int x = 4; int *p = &x; int *k = p++; int r = p - k; printf(“%i\n”, r); The output was 1 can anyone explain why??!
3 ответов
+ 2
As Bahha🐧 has stated, the code raises an error. I think instead of
int* k = p**;
the original line was
int* k = p++;
because then one would be the correct output, since pointer subtraction yields the distance between pointers, i.e. the amount of memory blocks the pointers are apart from each other, where the block size is defined by the size of the data type they are pointing two.
By post-incrementing 'p', the pointer 'k' would point to 'x', while 'p' now points to the next memory cell, so the distance between them is one.
+ 1
it should output an error because
int *k = p**;
doesn't make any sense.