Someone Please Explain this code

Question

import re

pattern = r"1(23)(4(56)78)9(0)?"

match = re.match(pattern, "1234567890?")
if match:
print("grupo :",(match.group()))
print("grupo 0:",(match.group(0)))
print("grupo 1:",(match.group(1)))
print("grupo 2:",(match.group(2)))
print("grupo 3:",(match.group(3)))
print("grupo 4:",(match.group(4)))
print(match.groups())

Answer 1

it will match and print the no along with str"Grupo :-no
e.g.:-ans :-('grupo :', '1234567890')

('grupo 0:', '1234567890')
('grupo 1:', '23')
('grupo 2:', '45678')
('grupo 3:', '56')
('grupo 4:', '0')
('23', '45678', '56', '0')

Answer 2

Thank You.

Answer 3

Hey Aditya, Please help me with this as well.

https://www.sololearn.com/Discuss/2237518/unable-to-use-get_dtype_counts