How can I check if a list has alternate elements equal in python?

Question

How can I check if a list has alternate elements equal in python?

Answer 1

mylst = [2, 2, 2, 7, 7, 8]
You can use set(mylst) to see if any change occurs. What set does is that it removes any duplicates.
If mylst's and set(mylst)'s lengths are same then and no change occurred (no duplicate found) means mylst has no duplicates, otherwise it has.

Answer 2

maf is right. But if what you want is two successive elements being equal; then using set method will catch list like [2, 3, 2, 4], whereas there are no equal successive elements. In such case, use regex like this...

import re
def check_succcessive(lst):
pattern = r".*(.)\1"
lst = [str(i) for i in lst]
lst = "".join(lst)
if re.match(pattern, lst):
return True
return False

#Hope it helps

Answer 3

https://code.sololearn.com/cBD87XgLp0HF/?ref=app