Heya can u help me. I have a problem in c

Question

code is
#include<stdio.h>
# include<conio.h>
int main()
{
char str[10][10];
int i,n;
print("enter no. of students");
scanf("℅d",&n);
for(i=0; i<n; i++)
{
printf("enter name of student : %d" i+1):
gets(str[i]);
}
printf ("student names are");
for(i=0; i<n;i++)
{
puts(str[i]);
}
getch();
return 0;
}

I m getting enter name of student 0 and enter name of student 1 by default
why plz help

Answer 1

#include <stdio.h>

int main (void){
char str[10][10];
int i, n;

printf("Enter no of students: ");
scanf("%d",&n);
/*
When number are fed into by keyboard, number are stored in the memory location
addressed by the variable and the return key remains in the keyboard buffer
It is transferred to the the string variable next in the line.
That's why you are facing problem.

Make use of fflush (stdin) to clear the keyboard buffer.

*/
fflush(stdin);
for (i=0;i<n;i++){
printf("Enter the name of the student #%d: ", (i+1));
gets(str[i]);
}

printf ("Student Names are: \n");
for (i=0;i<n;i++){
puts(str[i]);
}

return 0;
}