- 1
Write a code using do while loop to read the numbers until -1 and also count the +ve, -ve & 0's encountered by the users
In C programming correct me #include<stdio.h> int main() { int n,p=0,ne=0,z=0; printf("Enter your number:%d"); do { scanf("%d",&n); if(n>0) p++; else if(n<0) ne++; else(n=0) z++; } while(n==-1); return 0; }
2 ответов
+ 1
else if(n==0)
z++;
[else (n=0) is assigning, not comparing..and put ; at end if you are assigning like else n=0; ]
n=0 assigning..
n==0 is comparing...
After after while exit, print the calculated results,..
Before return statement...
+ 1
Sk Kaleshavali else n=0 It will give you an error.bcoz In else statement we need not to put any conditions.That's why if all the conditions are false then only your else statement excuted.
(Sorry for bad English)