Any one help on this and pliz explain?? ..PYTHON3..

Question

x=4
y=2

If not 1+1==y or x==4 and 7==8:
print("yes")
elif x>y:
printf("no")

Answer 1

x=4
y=2

if (not 1+1==y) or (x==4 and 7==8): # "if" needs to be in lower case letters
print("yes")
elif x>y: # "elif" needs to have same indent as if
print("no") # it is "print()" not "printf()"

# There are 3 conditions if if expression, and they can be seen as: (not 1+1==y) or (x==4 and 7==8) according to the operator precedence. (not 1+1==y) => False and also (x==4 and 7==8) => False. So if expression gives False. elif expression x>y => True, so "no" will be printed.

Answer 2

If statement will not execute, i guess. Because condition is false.
So elif __> no is the answer.