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Why this code has no output?
char *str = "12345"; printf(" %s", *str);
1 ответ
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*str means you are dereferencing a character, at the address pointed by pointer <str>. The problem here is you are using %s which is meant for string rather than character. Use %c instead of %s and you will get output.
Use %s if you want to print the string, but don't use dereference operator '*', -> printf(" %s", str);