0
Why does the error occurs
try: variable = 10 print(variable + "hello") print(variable / 2) except ZeroDivisionError: print("Divided by zero") except (ValueError, TypeError): print("Error occurred") What about print(variable/2) Why this doesn't run??
3 ответов
+ 3
variable is integer type there. Cannot be added to string..
Write like print( str(variable) +"hello")
Edit:
Nomita Patwal
print(variable/2) is fine and prints 5.0
str(variable) won't change original variable, just converts in print function..
variable = str(variable) will change original variable to string equivalent..
Check in playground..
+ 3
you are trying to concentrate a number and a string.
print(str(variable) + "hello")
+ 1
Look mam.
In your code, variable is a integer number and hello is a string cause it is a letter and it has " ".
But we cant add a integer with a string as you did in first print statement .
So you need to convert the integer into string .
str(10)
After this you can add both of them .
On the other hand you can print both of them . Like ,
print(variable, "hello")
This means that your are printing them one after another but not adding them.
.
So if you want to add them , than you have to convert them...or if you just want to print them one after one then use method 2.
.
Happy coding mam....