Could you please explain to me all type conversions of the following program section (e.g. "In partial output x+y implicitly con

Question

double a = 5.5;
long b = 2;
float c = 3.3f;
a = (b * c) + (c / a);
int d = ( int )(b + c);

Answer 1

In the third line :
The first bracket will get executed which multiplies b and c. b is a long and c is float data type so the answer of b*c would be in float type. Then the second bracket of third line which divides c to a. c is a float type and a is double so the answer of c/a would be converted to double.
Then the answer from 2 brackets will be added means float + double which will result in double.
At third line you got a double value let's move to last line.
in last first we will solve the bracket which is b+c b is a long and c is float so the resultant will be a float value which would get converted into int.

Hope you got it

Answer 2

Mohammad Ala Tahhan that's the fourth question of yours in a row (successively): are you doing bagde hunting? Please kindly avoid spamming QnA ^^