Method not returning the array. Pls suggest the proper solution.

Question

//method to find factors of a number
public static int[] factors(int x)
{
int i,rem=1,count=0,j=0;
for(i=1;i<=x;i++) //this loop counts the number of factors
{
rem=x%i;
if(rem==0)
count=count+1;
}
//System.out.println(count);
int[] arr = new int[count];
for(i=1;i<=x;i++) //loop to assign values to array
{
rem=x%i;
if(rem==0)
{
arr[j]=i;
//System.out.println(arr[j]);
j=j+1;
}
}
return arr;
}

Answer 1

it works, try:

import java.util.Arrays;

public class Program {
public static void main(String[] args) {
int[] f = factors(10);
System.out.println(Arrays.toString(f) );
}

//method to find factors of a number
public static int[] factors(int x){
// ...
}
}

Answer 2

Hello Denise,
Thanks for your response

Answer 3

The problem is the way how you try to print the result array
System.out.println(factors(10));
you get then something like
[I@4617c264

Answer 4

Deepak Sandha

to print Arrays:

Array.toString() and for multidimenaional arrays Arrays.deepToString().

Answer 5

Hello Deepak Sandha

Can you explain your problem?

Does the method not return the array or not a correct array?

in your main:
int[] arr = factors(5);

What happens? What would be the expected output?

Answer 6

/*Output should be factors of 10 i. e.
1
2
5
10*/
//but output is something else

public class Program
{
public static void main(String[] args) {
System.out.println(factors(10));
}
//method to find factors of a number
public static int[] factors(int x)
{
int i,rem=1,count=0,j=0;
for(i=1;i<=x;i++) //this loop counts the number of factors
{
rem=x%i;
if(rem==0)
count=count+1;
}
//System.out.println(count);
int[] arr = new int[count];
for(i=1;i<=x;i++) //loop to assign values to array
{
rem=x%i;
if(rem==0)
{
arr[j]=i;
//System.out.println(arr[j]);
j=j+1;
}
}
return arr;
}
}

Answer 7

Thank u
Zemiak and Denise
now I got it