whats wrong?

Question

public class Program
{
public static void main(String[] args) {

double x = square (2 , -7 , -72);
System.out.println (x);
}

public static double square (int a , int b , int c){

return -b +- Math.sqrt (b^2 - 4 * a * c) /2;

}

}

Answer 1

You just need to enclose the equation in parentheses and then divide by 2.

return(-b + Math.sqrt (b*b - 4 * a * c))/2;

Answer 2

yahel you're welcome.
Nice to know that I could help.

Answer 3

yahel you have written it just like you would solve it on paper. This will not work for a couple of reasons-

1) In return, the use of +- is wrong.
2) b^2 is an XOR operation and not a power operation.
3) There will be 2 roots, so you need to store it in an array and return the array.

Try making these changes and it should probably get you close to the solution.

Answer 4

whats the problem now? :

public class Program
{
public static void main(String[] args) {

double x = square1 (1 , -4 , 4);
double y = square2 (1 , -4 , 4);

System.out.println (x);
System.out.println (y);

}

public static double square1 (int a , int b , int c){

return -b + Math.sqrt (b*b - 4 * a * c) /2;

}
public static double square2 (int d , int e , int f){

return -e - Math.sqrt (e*e - 4 * d * f) /2;

}

}

Answer 5

Avinesh thank you!!! its working...