Anyone plaese answer the question?

Question

Suppose, you have a revolver & you have bullets in it. You know that a revolver has a shell in it to keep all the bullets, and the shell is a circlular typed. And normally in that shell it can contain 6 bullets. But now, you are given the radius of that circular typed shell (R), and also given the number of bullets in it(n), now you have to figure out that what is the radius of one bullet(r) which is in the revolver shell.
Its a type of math problem. I'am giving you the input & output:
Input:
R n
4 6
4 17
3.14 100
42 2

Output:
r
1.3333333333
0.6209067545
0.0956260953
21

anyone please help me to solve the problem.
Thanks in advance❤

Answer 1

bluesea thank you❤
But i can't relate with the equation you showed above & then you said.
If you break down the equation please,...
First, R*(cos(pi-pi*2/n)))
what we get form the line?
then, cos(pi-pi*2/n)
then, pi-pi*2/n
then, pi*2/n
& after the '+' sign
if you break down the equation,...

Answer 2

bluesea how can i write cos(f)=r/R-r?

Answer 3

bluesea i meant how cos(f) and r/(R-r) are same? How these two side are same?

Answer 4

okay, thank you bluesea