Ordered or Unordered sequence

Question

I am facing a problem in solving the question below:- (can someone please help????)

Write a program that reads a sequence of integer numbers and outputs true if the sequence is ordered (in ascending or descending order), otherwise, false. Keep in mind, if a number has the same value as the following number, it does not break the order. The sequence ends with 0. Do not consider this number as a part of the sequence. The sequence always has at least one number (excluding 0).

code which I wrote(For this code I am getting runtime error).....

```import java.util.Scanner;
class Main {
public static void main(String[] args) {
// put your code here
Scanner scanner = new Scanner(System.in);
int number1 = scanner.nextInt();
int number2 = scanner.nextInt();
int number3 = scanner.nextInt();
int mid = number2;
int next = number3;
int prev = number1;
int flag = 1;
boolean val = true;
if (number1 > 0) {
while (val) {
if (prev <= mid && mid <= next || prev >= mid && mid >= next) {
flag = 1;
int number4 = scanner.nextInt();
prev = number2;
mid = number3;
next = number4;
} else {
flag = 0;
}
}
}
if (flag == 1) {
System.out.println(true);
} else {
System.out.println(false);
}

}
}```

Answer 1

while (val) is always true