Extract the first word using a lambda function

Question

Description of the task:

Black Box (str -> str)
Hello world => Hello
a word => a
don't touch it => don't
greetings, friends => greetings
... and so on ... => and
hi => hi

***We need to use just only a lambda function!

My attempt:

lambda s=' ..., first word': [((i*(i.isalpha()) or i) for i not in ' .,') for i in s.split()]

Answer 1

Thanks, Valmob101, you are cool!
I've a little bit modified your function, and so, we've got it!)

The right answer is:

lambda s: str(''.join([i for i in s.split() if i[0].isalpha()][0])).split(',')[0]

Answer 2

Use this:

c = ".,.,.. hello world"
a = (lambda x:[i for i in x if i[0].isalpha()][0])(c.split())
print(a)

Answer 3

Valmob101, I've written the same yesterday
([i for i in s.split() if i.isalpha()==True][0])
, BUT
it doesn't pass words like "don't", or like "comma,". We need to except symbols , and '.
Take note of the description

Answer 4

Andrex also try this:

https://code.sololearn.com/ce2eSWQwzv0M/?ref=app

Answer 5

>>>s= lambda x: x[:x.index(' ')]
>>>print(s('hello world'))
hello

Answer 6

Andrex , I fixed my answer(added [0] to i). Let me know whether this is what you want.