how can I find the index of the second repetition of a string?

Question

f = open("newFile.txt", "w+")

pathName = os.path.abspath(f.name)

#I need to find the index of the second repetition of the back slash

Answer 1

On an index note, see here:
https://code.sololearn.com/cT1BcIt41D02/?ref=app

Answer 2

Do you mean second instance, or second repetition (i.e. 3rd instance)?

I would recommend regex for this.

import re

string = 'hello//world//ygc'

print(re.match(r'(?:.*?/.*?/.*?)/', string).end() - 1) #12 3rd instance.

print(re.match(r'(?:.*?/.*?)/', string).end() - 1) #6 2nd instance.

Answer 3

Kuba Siekierzyński Very nice! You win this regex round! 😉

Answer 4

Russ I used to love this game :) Reminds me of some very good time in my life ;)

Answer 5

the back slash is repeated about five times in the string and I want to find the index of the second backslash.

Answer 6

I’m not really understanding. Specially the “(?:.*?/.*?)”