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Why "super().__init__()" one argument less than the "base class.__init__()" ??
The question related to the below code https://code.sololearn.com/c7wL49kmf8j9/?ref=app
1 ответ
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That's because self is an implicit argument.
instance.f() internally gets converted to class.f(instance).
For a detailed explanation read this:
https://code.sololearn.com/ce664AekBveN/?ref=app