the default value of char in c

Question

#include <stdio.h>
int main()
{
int a= 13;
unsigned int b =37;
char c ;
printf("%d%d%d", a, b, c);
getch();
}
the output is 13 37 0
(i)why the char value is 0?
(ii)when there is no initialization of 'a' and 'b'
why the output of 'c' is random values?

Answer 1

Whenever you declare a variable, system allocates some writable memory for it. If you don't initialise it then it will contain any *garbage value* at that memory location.

Answer 2

Could be because of where the information is kept. If you used new char maybe you wouldn't have the same problem. Maybe

Answer 3

Any variable that declared hold garbage value.

Answer 4

why 'c' has dependency on 'a' and 'b' ~ swim ~

Answer 5

This is why you initialize variables :)

Answer 6

so when c is not initialized and has no dependency on either 'a' or 'b' then why the 'c' value is not same in both cases
~ swim ~

Answer 7

when used new char d and initialized 'a' and 'b'.
o/p of 'c' is random but of 'd 'is 0
Davide Floccari