How does this code work?

Question

(n + rand() % x)
Where n & x are integer numbers
I eant know, how does this function use n & x ??

Answer 1

Rand() is a function in c++ that returns a random whole number(int) beetween 0 and RAND_MAX (for more information look at rand() reference in c++ documantation)

n and x are variables, as you said of type int (0,1,2,3,565,1000, -20...) and they are declared in the user input or hardcoded into the program

% - mod - it returns the leftover of division beetween two int numbers i.e. (25 % 6 = 1)

% has higher priority than + operator

Therefore , this program will return value of
Case 1 : (n + random int) if x is higher than rand
Case 2 : (only n) if x is equal to that random value
or Case 3 : (n + leftover) if x is lower than random int

Answer 2

n and x are variables they have to be declared some where earlier in the program.

https://code.sololearn.com/c0J9eryN6Fq8/?ref=app

Answer 3

Kristijan Fajdetic
I want to understan, why does the output be greater than x??
Isn't x value the range of rand?

Answer 4

No rand() is a solo part if this equation.
The equation says
Number n plus a random number
Then
Take the result and get modulus using x

N=1
Random number example 6
X=2
1+6 = 7
7%2 = 1 (read remainder of 7/2)

N=3
Random number example 5
X=4
3+5 =8
8%4 = 0 (read remainder of 8/4)

http://www.cplusplus.com/reference/cstdlib/rand/

ok. This article says that you can use the modulus (x) to define the range. But that is not a parameter of the rand- method.

n is offset
x is maximum number

Have a look at my code I added some extra explanation.