* Beginner Project Idea *

Question

LYCHREL NUMBERS

This only works on Non Lychrel #s

Take a number, add it to its backward self, and the sum is checked to be or not to be a palendrome. if it is not, it runs again with its new number (the sum) and checks that. ultimately getting to a palendrome and revealing how many runs it took. if it fails, that was a Lychrel #

example -
47
47 + 74 = 121
1 Try reveals a palendrome

example #2 -
349
349 + 943 = 1292
1292 + 2921 = 4213
4213 + 3124 = 7337
3 Trys reveals a palendrome

Answer 1

https://code.sololearn.com/cq9Q13gtfY7r/?ref=app

you can take help from above link.

Answer 2

c# plesae

Answer 3

fun fact. 196 for instance has been run on a super computer over a billion iterations resulting in numbers over 400,000,000 digits long and still nothing.

Answer 4

Great idea.
This is the code i made:
https://code.sololearn.com/caorAziv04Zk/#py

Answer 5

cool idea

Answer 6

As I have just started learning ruby i gave it a try:
Chech out my Code Lychrel

Answer 7

Get the number and convert to String using str(). Reverse the string using slice syntax [::-1]. Convert the reverse string to int using int(); Check if the initial number and the reverse number are equals. If not, increment the attempt and execute all again.

Answer 8

How I did it. Maybe not the best way, but it got me the result I needed.

run=True

def flip(x):
x=str(x)
x=x[::-1]
x=int(x)
return x

def check(a,b):
global trys
print(a, end=' ')
print("+", end=' ')
print(b, end=' ')
print("=", end=' ')
c=a+b
print(c)
d=flip(c)
if c == d:
print()
print("The Palendrome Is %d" % c)
print()
print("Solved in %d runs" % trys)
else:
trys+=1
check(c,d)

while run == True:
trys=1
print("\n"*2)
number=input("Enter A Number - ")
print(number)
print("\n")
numberFlip=flip(number)
number=int(number)
check(number, numberFlip)

Answer 9

nice

Answer 10

you want it in c#, write it in c# and show us. this is just a simple project for beginners.. I would like to see it in c#

Answer 11

Nice code Daniel!

Answer 12

Thank you guys very much I appreciate your kind help