If a=5 b=25 n=4, why output is zero?

Question

#include <stdio.h>

int main()
{
int a,b,n;
float result;
printf("First value=\n");
scanf("%d",&a);
printf("Second value=\n");
scanf("%d",&b);
printf("Select\n\t1.Summaton\n\t2.Substraction\n\t3.Multiplication\n\t4.Division\nChoose an option=\n");
scanf("%d",&n);

switch(n)
{
case 1:
result=a+b;
printf("Summation=%f\n",result);
break;
case 2:
result=a-b;
printf("Substraction=%f\n",result);
break;
case 3:
result=a*b;
printf("Multiplication=%f\n",result);
break;
case 4:
result=a/b;
printf("Division=%f\n",result);
break;
default :
printf("Wrong option");
}
return 0;
}

Answer 1

You should convert a and b into floats before division.

Answer 2

because in case 4
result = a/b
since a and b are int data type.
and a < b so a /b = 0.
if a or b were float it would give the correct result with decimal places.

Answer 3

Tanjir Ahmed here is your code modified ... change a and b to floats then as a bonus use %e instead of %d as you are assigning both as float pointers.

https://code.sololearn.com/cyk0Y254B1Fv/?ref=app