Skee-ball test case 3 python Code Coach

Question

Hi there,
Getting false for the third case. Checked here https://www.sololearn.com/discuss/2130536/?ref=app
https://www.sololearn.com/discuss/2154724/?ref=app
an nothing helped.
Also tried the extreme case like 24, 2. and (code worked well on pycharm)
this is my code:

import math
score = int(input())
price = int(input())

if score != 0:
gained = (score / 12)
tickets = math.floor(gained)
else:
print("Try again")

if tickets >= price:
print("Buy it!")
else:
print("Try again")
please help

Answer 1

Just delete lines 1, 4-10, calculate instead of this in line 11. That's everything.

Answer 2

If "score" is 0, "tickets" is never defined and you get a NameError.

Answer 3

Thanks :)

Answer 4

You're getting much too complex for the task. It was not requested to round anything anyway.

Answer 5

And there's no need to exclude the zero from this calculation...

Answer 6

Ive tried adding
tickets = 0 before the first if statment, it didnt help, also when getting zero as score output will be Try again

Answer 7

Simple & stupid 😉👍

Answer 8

I am also getting error only for the third case.

My code:

score=int(input())
price=int(input ())
if (score//12)>price:
print('Buy it!)
else:
print(Try again')

It is locked and I can't see why does it gives me a wrong output

Answer 9

x=int(input())
y=int(input())
if ((x/12)>=y):
print("Buy it!")
else:
print("Try again")

It's simple and easy try copy pasting in exact same way.