Explain this please

Question

https://drive.google.com/file/d/1W2vMIe8BtwGlO3uusxtHRpeUUU_yEMhY/view?usp=drivesdk

Answer 1

Lets take it step by step..

let [learn, solo] = "learn";

This destructures "l" into `learn` and "e" into `solo`. The fact that the `solo` variable has a default value, like

let [learn, solo = "solo"] = ...

does not matter, since there are enough letters in your string to fill both variables.

This line

[solo, learn] = [learn, solo];

is the same as

[solo, learn] = ["l", "e"];

It destructures "l" into `solo` and "e" into `learn`.

The last line simply adds "l" and "e" together.

Answer 2

🆇🆈🅼//Inactive It can have an effect, if the string is too short.

Consider this:

let [learn, solo = "banana"] = "X";

Here `learn` obviously gets the "X", but then we have no more letters to give to `solo`.

So, `solo` would keep it's default value of "banana".

But in the challenge question there are enough letters, so `solo` gets overwritten so to say :)

Answer 3

Schindlabua so it's not possible to pass on a value in destructucturing ?

Like here : solo="solo"

Has no effect?

Answer 4

Schindlabua okay, I understood,

Thank you very much Sir