Whats wrong with my division function void mod() it doesn't work all the others do.

Question

#include <iostream>
using namespace std;

void add(int a, int b)
{
int z = a + b;
cout << "Sum"" " << z << endl;
} /*creates the addition function*/

void subtract(int c, int d)
{
int f = c - d;
cout <<" The result is:" << f << endl;
} /*creates the substraction function*/

void times(int x, int y)
{
int m;
m = x * y;
cout << "Product:" << m;
cout << endl;
} /*creates the multiplication function*/

void mod(int e, int v)
{
int s = e / v;
cout << endl;
} /*creates the division function*/

int main()
{
cout << "Calculator" << endl;
cout << "Input value_1:" << endl;
int q;
cin >> q;
cout << "Input value_2:" << endl;
int o;
cin >> o;
cout << "Select a mode:" << endl;
cout << "1.Addition\n";
cout << "2.Substraction\n";
cout << "3.Multiplication\n";
cout << "4.Division\n";
int w;
cin >> w;

if (w == 1)
{
add(q, o);
}

if (w == 2)
{
subtract(q, o);
}

if(w==3){
times(q,o);
}

if(w==4){
mod(q,o);
}
return 0;
}

Answer 1

You are not printing anything in mod(), hence there is no output. Other than that, I don't see any errors.

Just in case you are expecting a floating-point number as a result when e.g. dividing ten by four: Dividing an integer by another integer will yield an integral result in C++, i.e. the result is stripped of its decimal part. At least one of the operands is required to be a floating-point type to produce a floating-point value as result, in which case it would need to be stored in a variable of type float or double as well.