How to fix this error so that num = [1,3,4] ?

Question

lst = ['#',1,3,'*',4]
num = []
for n in list:
if type(n) == int:
num = num.append(n)
print(num)

Answer 1

Your mistake in line3, 5:

Fixed👇:
lst = ['#',1,3,'*',4]
num = []
for n in lst:
if type(n) == int:
num.append(n)
print(num)

Answer 2

My solution is a bit different.
#How to fix this error so that num = [1,3,4] ?

lst = ['#',1,3,'*',4]
nums = []

for i in lst:
i = str(i)
if i.isdigit():
nums.append(int(i))

print(nums)

Answer 3

Anyways to get the answer you need to use try and except where while iterating you try to convert a value into an int if it fails then you except that and continue. since 1,2 and 4 would be able to get converted cause they already are int's it will work and give you the desired output.
here is the code:
lst = ['#',1,3,'*',4]
num=[]
for n in lst:
try:
num.append(int(n))
except:
continue
print(num)

Answer 4

Alternative using list comprehension

num = [ e for e in lst if type(e) is int ]

Answer 5

Kunsh-Tyagi
Ipang has written a correct & elegant solution as has Vadi velan

Answer 6

This isn't possible as you cant use type() to iterate something