how to find number of digits in a given number in python or C++ (for example : 345 has 3 digits)?

Answer 1

In python:

Loop through the number (I think you might need to convert it
to string first) ,and check whether the type is int using type(firstnumber)==int ,if yes, increment a varaible(let assume it is count initialized with value as 0)
Edit: you can simply do as the upper solution would take more operations to do

len(str(345))

Answer 2

decoder
Convert it to string using str() function
Then use len() function to count.
len(str(377)). #o/p:- 3

Answer 3

In python you can change int to str then store this int variable and make condition for character in this string variable if this character is digital increase a counter : count += 1 .Finally return this counter variable.You can make all this code in a function.

Answer 4

One way is to keep dividing by ten and increase the result from 0 at the same time until the number itself is 0.

Answer 5

If you convert to string and count characters, be sure to handle potential for a negative sign or a decimal character.

If it is a whole number, then you can determine it mathematically. Find the magnitude by taking the log (base 10) and truncating the result to its integer floor. Then add 1 to get the number of digits.

Use absolute value if the number may be negative.

Log fails if the input number is zero, however, so make a special case for that.

In C++:

int num = 345;
ndigits = (num ? trunc(log10(abs(num)))+1 : 1);

https://code.sololearn.com/cGN8zCE1fPxa/?ref=app

Answer 6

1. Convert it to string
2. Find its length

Answer 7

#In python
n=int(input())
Count=0
while n!=0:
Reminder=n%10
count=count+1
n=n//10
print(count)