How do I do this???

Question

Drag and drop from the options below to create a new set "c", with only the values common to both "a" and "b", if not all of the values of set "a" are contained in set "b".

let a: Set = [1, 2, 3]
let b: Set = [3, 5, 2]
if ! a. b) {
let c: = a.(b)
}
isSuperset(of: I
sSubset(of:
intersection
union
Set
subtracting

I need helpppppppppppppp

Answer 1

Generally
Union of 2 sets results to combining set of a and b with all values. So yours =>[1,2,3,5]
Intersection of a and b sets results to values common to a and b sets.. So =>[2,3]
Substraction a-b sets gives the values from a which are not in h so [1].

Answer 2

I give an example of Swift 4 code:
var set1: Set = [1, 2, 3, 4, 5, 6]
var set2: Set = [5, 6, 7, 8, 9, 0]
var set3: Set = [7,9]

print("1",set2.isSubset(of: set2))
print("2",set2.isStrictSubset(of: set2))

print("3",set3==set2)

print("4",set2.isSuperset(of: set3))
print("5",set2.isStrictSuperset(of: set3))

print("6",set2.isDisjoint(with: set3))
print("7",set1.isDisjoint(with: set3))

/* print
1 true
2 false
3 false
4 true
5 true
6 false
7 true
*/

This should clear all your doubts... 😀😀😀