#include <stdio.h> main() { int i; for(i=0;i<5;i+=4) { i=i*i; } printf("ans %d",i); return 0; }

Question

Loop problem, in which how we get ans 20 .

Answer 1

Loop1:
i = 0
i = i * i //still 0
i += 4 //from loop

Loop2:
i = 4
i = i * i //16
i += 4 //20

Answer 2

When i is 0 we will check condition i<5 (0<5) it true then i=i*i means 0*0 so i=0 then next time i will increase by 4 means i+=4 which is
i=0+4 here i will be 4 then it will check condition i<5 and i is 4
4<5 condition true then
i=i*i = 4*4 means 16 it will assign to i after that it will increase by 4
i+=i (i=16+4) which is 20 so we will again check condition i<5 and i is 20
20<5 which is false so last value will print 20 as a Output.

Answer 3

At i =0 we have i=0*0 ,i=0,then

Edit: At i=4 we have i=4*4,i=16,then
i+=4 and loop stops with i=16+4=20

Answer 4

Abhay answer is 20. Read your answer again please.

Answer 5

🔫 Rick Grimes just realised ty