Skip a duplicate value when we use While condition

Question

Syntax:-

i = 1
while i<=5:
print(i)
i+=1
if i==3:
print("Skipping 3")
continue

Output:-

1
2
Skipping 3
3
4
5

My doubt is though we mentioned it as print when i==3 as "Skipping 3" why does it pick 3 in next line? if we want to restrict such how to fix it?

Answer 1

Put print(i) and i+=1 after if block

Answer 2

Btw: Have you tried to use sets to eliminate dublicates?

nums = [1,1,2,2,3]
distinct_nums=set(nums)
print(distinct_nums)
>>> {1,2,3}

If you realy need a list, you can then back cast with list() again.
That should be rather fast, because its implemented in C.

Answer 3

Add i+=1 before continue too

Answer 4

continue just goes up the loop, so putting it at the bottom is pointless, continue isn't even needed here you can just increase i when i is 3 to avoid printing it:
i = 1
while i <= 5:
print(i)
i += 1
if i == 3:
i += 1
print("Skipping 3")