Sorting array of strings

Question

Hello I want to sort a array containing strings such that the last letter of the string is the first letter of the next string in python.
Eg:
['abcd' , cba', ' def']
output
['cba', 'abcd','def']

Answer 1

I don't think that this can be done with sorting. It looks like a similra task from LeetCode named ? destination.

paths = [["London","New York"],["Lima","Sao Paulo"],["New York","Lima"]]

task description is: You are given the array paths, where paths[i] = [cityAi, cityBi] means there exists a direct path going from cityAi to cityBi. Return the destination city, that is, the city without any path outgoing to another city.

Answer 2

['abc','sdf','qwe']
what will be the output?
Also show your attempt.

Answer 3

Hai Samsil Arefeen I have not done but i think this problem can be solved by nested for loop .
The output for this testcase ['abc','sdf','qwe'] is -1

Answer 4

Hello guys I am sorry i have not entered the question properly in that question they will give the two inputs the first one is array and the second one is the string to start with.
The first word means where to start
Here is the code
array=list(input().split())
first_word=input().strip()
result=[]
result.append(first_word)
count=0
for _ in range(len(array)):
for i in array:
if i[0]==result[count][-1]:
result.append(i)
array.remove(i)
count+=1
if result:
print(*result)
else:
print(-1)
Eg:1)
Array=['abcd' , cba', ' def']
first_word='cba'
Output
cba abcd def
2)
Array=['abcd' , cba', ' def']
first_word='abcd'
output
abcd def