How do i make it not say none

Question

import random
random_player = [1, 2]
random_player2 = random.choice(random_player)
random_values = ["1", "22", "333", "4444", "55555", "666666"]
random = random.choice(random_values)
def non_toxic():
print("good game")
return

def toxic():
for i in random:
print("ez")
continue
return

if random_player2 == 1:
print(non_toxic())
else:
print(toxic())

Answer 1

some issues:
1. please check indents
2. random is a module, you should not name a variable like that.

Answer 2

You're not returning anything from function so then remove return in function definition..
And also just put like this..

if random_player2 == 1:
non_toxic()
else:
toxic()

Answer 3

random_values = ["1", "22", "333", "4444", "55555", "666666"] use this as it is. Here values are strings but in your modified code list have numbers. Don't work for loop iterable.
Thinkboy123 corrected code :

import random
random_player = random.choice([1, 2])
random_values = random.choice(["1", "22", "333", "4444", "55555", "666666"])
def non_toxic():
print("good game")

def toxic():
for i in random_values:
print("ez") #add ident here

if random_player == 1:
non_toxic()
else:
toxic()

Answer 4

ok

Answer 5

import random
random_player = random.choice([1, 2])
random_values = random.choice([1, 22, 333, 4444, 55555, 666666])
def non_toxic():
print("good game")

def toxic():
for i in random_values:
print("ez")

if random_player == 1:
non_toxic()
else:
toxic()
is this good?

Answer 6

thank you brother

Answer 7

You're welcome..