Why the answers are being different only by changing the position of break function? "alert show 'sum=1tum=3"

Question

var sum =0;
for (i=0;i<=3;i++){
if (i==2){
break ;}
sum+=i;
}
var tum =0;
for (e=0;e<=3;e++){
tum+=e;
if (e==2){
break ;}
}
alert ("sum="+sum+"tum="+ tum);

Answer 1

The first one sum doesn't increase by 2 because the loop already breaks before it.

The second one tum does because it increases before the loop breaks.

The order matters.

Answer 2

its not changing position of the break statement. its moving the "add to sum" statement.

for every loop in the three loops i is incremented by 1 and AFTER that the sum is incremented by i. It starts at 0, then its 1, then when i becomes 2. But before it can add that 2 to the sum, it breaks so sum == 1.

The second for loop adds to tum BEFORE the break check, so when e is 2, it adds e to tum BEFORE breaking, wthats why its 3, 0+1+2 = 3.

Answer 3

e=0
tum=0
e=1
tum+=e (tum=1) 1
e=2 +
tum+=e (tum=3) 2
e=3 +
tum+=e (tum=6) 3
=6

Answer 4

It is still hard to understand 😔

Answer 5

Please friends ,keep explaining me step by step 🙏🙏🙏🙏🙏🙏

Answer 6

I write "e<=3 "so the answer seems 0+1+2+3=6 and then break .after it how the answer reach to 3 from 6 .🙏🙏🙏