The following code examine three variables -- x, y, and z -- and prints the largest odd number among them. If none of them is o

Question

if x % 2 == 1 :
if y % 2 == 1 and x >= y :
if z % 2 == 1 and x >= z :
print(x)
elif y % 2 == 1 :
if x % 2 == 1 and y >= x :
if z % 2 == 1 and x >= z :
print(y)
elif z % 2 == 1 :
if x % 2 == 1 and z >= x :
if y % 2 == 1 and z >= y :
print(z)
else :
print('All three numbers are even')

Don't the if statements in these questions result in the interpreter never reaching the else statement?

Answer 1

print(max(filter(lambda x:x%2!=0,(x,y,z))))

Answer 2

Do you really have to use all those if...elif...else block? there is an alternative by using tuple comprehension with odd number filter, tollowed by use of built-in max() on the tuple to find largest number.

Answer 3

x, y, z = 10, 14, 76

# create a tuple of odd numbers
odds = tuple( n for n in (x, y, z ) if n & 1 )

# <result> is max of tuple elements (if there is anything in the tuple). Otherwise None.
result = max( odds ) if odds else None

print( result )

Answer 4

Ipang Great. How can I do that?

Answer 5

import timeit
start=timeit.default_timer()
print(max(n for n in (1,2,3) if n & 1))
print(timeit.default_timer()-start)

start=timeit.default_timer()
print(max(filter(lambda x:x%2==1,(1,2,3))))
print(timeit.default_timer()-start)

start=timeit.default_timer()
print(max(n for n in (1,2,3) if n%2==1))
print(timeit.default_timer()-start)