Passing 2d array in function

Question

How i can pass a 2D array in function

int mtx[2][3];
int MAX;
MAX = arr_max(mtx); <~~ here i got in error

Answer 1

See this

There are three ways to pass a 2D array to a function:
The parameter is a 2D array

int array[10][10];
void passFunc(int a[][10])
{
// ...
}
passFunc(array);
The parameter is an array containing pointers

int *array[10];
for(int i = 0; i < 10; i++)
array[i] = new int[10];
void passFunc(int *a[10]) //Array containing pointers
{
// ...
}
passFunc(array);
The parameter is a pointer to a pointer

int **array;
array = new int *[10];
for(int i = 0; i <10; i++)
array[i] = new int[10];
void passFunc(int **a)
{
// ...
}
passFunc(array);

For better explanation you can read this post .i copied these from stack overflow

https://www.google.com/amp/s/www.geeksforgeeks.org/pass-2d-array-parameter-c/amp/

Answer 2

♨️♨️ i can't use the way number three to solve my problem becouse i'm using C . So i think malloc and calloc can do the work 😃 . Thank u🙏🏻