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Write a function that computes the biggest product of 2 adjacent digits
the number is large_number = "6265625639770930589729165948157604396883137944753038530630802554971098857083971475495106467594633963" how can I write a python function to find the biggest product of 2 adjacent digits in the above number ? Than you!
8 ответов
+ 6
Velouria Darkstar , before we can help you, you should do a try by yourself first. put your code in playground and link it here. Thanks!
+ 6
thanks for sharing your code. here is the approach i made.
https://code.sololearn.com/coT03yYVzdfc/?ref=app
+ 3
Then use what you know! create a function that takes a string, then creates a list out of said string.
You know what to do after that
+ 1
No worries, thank you for the attempt. Check this out:
https://code.sololearn.com/cVGsOLTQFX0E/?ref=app
+ 1
Velouria Darkstar edited your code to get correct way.
Hope it helps to idenify correct approach of your way.
https://code.sololearn.com/c7tbMKG9ZemM/?ref=app
0
9*8=72 is the answer for this?
If yes, then find max(list(large_number))
Large_number.indexof(max)*large_number.indexof(max+1, or - 1), next
find next repeat this for from index max(list(str(large_number.substring(large_number.index(max)+1)).. If greater one replace it with previous one..
You said you know about array method so if this is same as you know, then ingore it.
0
(sorry I'm new here and very much struggling with Python)
I tried something like this but it's wrong because it keeps giving me 1,0,1,0....
the correct answer is supposed to be 72
import sys
def biggestProduct(string, m) :
n = len(string)
maxProd = (-(sys.maxsize) - 1, -(sys.maxsize) - 1)
for i in range(n - m) :
product = 1, 0
for j in range(i, m + i) :
product = product * (ord(string[j]) - ord('0'))
maxProd = max(maxProd, product)
print("Biggest Product =", maxProd)
if __name__ == "__main__" :
string = "6265625639770930589729165948157604396883137944753038530630802554971098857083971475495106467594633963"
m = 2
biggestProduct(string, m)
0
Hi