How to curry functions in python?

Question

I want to make this function simpler using currying.

lst = [i for i in range(100)]

def divisible_by_6(lst):
    new_list = []
    for i in lst:
        if i % 2 == 0:
            new_list.append(i)
    final_list = []
    for j in new_list:
        if j % 3 == 0:
            final_list.append(j)
    return final_list

divisible_by_6(lst)

Answer 1

Gyasi Sturgis
The answers given and your example are not currying but function composition.
I don't think that currying will make your original function simpler, if you want to make it simpler you can just do:
def divisible_by_6(lst):
return [*filter(lambda x:x%6==0,lst)]

Currying is about a function that splits its functionality into one or many unary(single parameter) functions. If you want an example anyway:
https://code.sololearn.com/c1956CiHV3Iv/?ref=app

Answer 2

Currying means? how?

Answer 3

Do you mean like this?

https://code.sololearn.com/cto6W0V7X8ta/?ref=app

Answer 4

like as in if
f(x) = x+3
g(x) = x+5 then
f(g(x)) = x + 3 + 5

Answer 5

yes Sousou thank you thats what i was looking for

Answer 6

lst = [i for i in range(100)]

def divisible_by_2(lst):
new_list = []
for i in lst:
if i % 2 == 0:
new_list.append(i)
return new_list

def divisible_by_3(lst):
final_list = []
for j in lst:
if j % 3 == 0:
final_list.append(j)
return final_list

def divisible_by_6(lst):
new_list = divisible_by_2(lst)
final_list = divisible_by_3(new_list)
return final_list

print( divisible_by_6(lst))

#like this? But it makes redundant code..

Answer 7

Exactly the same solution I thought, as by Sousou

https://code.sololearn.com/cSJQ9XbD2l39/?ref=app