what is function overloading? plzz help I don't understand...

Answer 1

#include<iostream>

using namespace std;

int sum(int, int);
int sum(int, int, int);

int main()
{
int a, b, c, choice;
char stop[20];
cout << "\na: ";
cin >> a;
cout << "\nb: ";
cin >> b;
cout << "\nc: ";
cin >> c;
do
{
cout << "\n\nif you want to sum a+b press 1+ENTER\nif you want to sum a+b+c press 2+ENTER\n------------------\nyour choice: ";
cin >> choice;
} while (choice != 1 && choice != 2);
cout << "\n\n\n";
switch (choice)
{
case 1:
sum(a, b);
break;
case 2:
sum(a, b, c);
break;
}
cout << "\n\n\nPress a letter/number+ENTER to exit ";
cin >> stop;
return 0;
}

int sum(int x, int y)
{
int tot = x + y;
cout << "x + y = " << tot;
return tot;
}

int sum(int x, int y, int z)
{
int tot = x + y + z;
cout << "x + y + z = " << tot;
return tot;
}

Answer 2

you can create 2 functions with the same name and return type, but with different arguments. So, when u call that function, the compiler use the most appropriate, according on what argument(s) u pass to the function.
If u want I can write an example ;)
Bye!

Answer 3

yes plzz!! :)

Answer 4

thanks:)

Answer 5

IMPORTANT: I recommend u to run the code I posted on a PC and not on "code playground", if u can, because there are several inputs.
As u can see, there are 2 functions called "sum", but the first function requires 2 int values ( sum (int x, int y)), whereas the second one require 3 int values (sum (int x, int y, int z)). So, when I call the function sum, and I pass it 2 int variables (a and b), the compiler uses the first function, whereas if I pass it 3 values (a, b and c), the compiler uses the second one.

Answer 6

U can do the same thing when u create 2 functions with the same number of arguments but with different data types.
For example "sum (float, int)" and "sum (int, double)".
U can overload as many functions as u want. For example "sum (int, int)", "sum (int, int, int", "sum (float, int, float)", ...

Answer 7

okay!!**

Answer 8

you are welcome :)
if u don't understand something just tell me!

Answer 9

thanks for your kindly support:)
tomorrow I will try this program in my PC
and if any doubt I just tell.....