Why output is 32....?

Question

https://code.sololearn.com/cOEWSo77ftGu/?ref=app

Answer 1

You are passing address of 'a' to fun, which has int* b now pointing to that address. So (*b) will print the value 3. Then you are modifying the value at address a by doing *b = 2. If now you print *b in main then it will return 2.
So you have 32 as result.

Answer 2

Thankyou so much but last question like *b=&a when we want to change the value in b is it automattically changed in a

Answer 3

Vikramjeet Singh yes.