can any one help me in my code

Question

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int longage2(char phe[ ]){
if (strlen(phe)==1||strlen(phe)%2!=0||phe[strlen(phe)]=='a'){
return 0;
}
for(int i=0;i<strlen(phe);i++){
if(i%2==0){
if(phe[i]!='a'){
return 0;
}}else{
if(phe[i]!='b'){
return 0;}}
}return 1;}

void longage4(char phe[]){
int a;char ph1[10];
for( int i=0;i<=strlen(phe)-1;i++){
ph1[i]=phe[i];
printf("%d\n",longage2(ph1));
if(longage2(ph1)==1){
a=i;
}}
printf("a=%d\n",a);
char ph2[a];
for(j=0;j<=a;j++){
ph2[j]=ph1[j];
}
printf("%s\n",ph2);
printf("%d",longage2(ph2));

}

int main()
{char phe[20];
printf("donnez un mot\n");
scanf("%d",phe);

longage4(phe);
return 0;
}

Answer 1

mar ia the problem is that ph2 has no terminating character '\0'

Also if you want ph2 to contain ph2[3] you should declare char ph2[4]; so char ph2[a+1];
adding another space for \0 it become:

char ph2[ a + 2 ]

for(j=0; j <= a; j++) {
ph2[i] = ph1[i];
}
ph2[a+1] = '\0';

Answer 2

The scanf in the main() should have %s
And you need to declare int j; into longage4()

Answer 3

Can you tell me what to enter as input?

Answer 4

Thank you very much for helping me. I don't know😦 how to express my thanks to you😀😊

Answer 5

I fex it but wan yo but (donne un mot and you raet abab l hav proplem in resolt of line 32

Answer 6

He raet to me "abab?"
I didnt no whay but (?)qustshen marc

Answer 7

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int longage2(char phe[ ]){
if (strlen(phe)==1||strlen(phe)%2!=0||phe[strlen(phe)]=='a'){
return 0;
}
for(int i=0;i<strlen(phe);i++){
if(i%2==0){
if(phe[i]!='a'){
return 0;
}}else{
if(phe[i]!='b'){
return 0;}}
}return 1;}

void longage4(char phe[]){
int a;char ph1[10];int j;
for( int i=0;i<=strlen(phe)-1;i++){
ph1[i]=phe[i];
if(longage2(ph1)==1){
a=i;
}}

char ph2[a];
for(j=0;j<=a;j++){
ph2[j]=ph1[j];
}
printf("%s\n",ph2);

}

int main()
{char phe[20];
printf("donnez un mot\n");
scanf("%s",phe);

longage4(phe);
return 0;
}

Answer 8

thes is beter an clen and the input is abab and mast be the reasolte is abab

Answer 9

The program works like this

When we enter (ab)^n n>0
the reasolt is (ab)^n
wen we but like exp : aba the resolt shod be :ab
He is looking for (ab)^n Consecutive and he Display it

Answer 10

Hug me 🤗🤗🤗

Answer 11

Hhhhh😊