can any one help me in my code ,he didn't work in my bc

Question

//have be the input is (abababaaaaaab)
//and the resolt is "Right"
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int longer(char phr[50],int i){
if(phr[i]=='\0'){
return 0;
}else{
return longer(phr,i+1)+1;}}
int occurrence(char phe[],char a){
int k=0;
for(int i=0;i<=longer(phe,0);i++){
if(phe[i]==a){
k=k+1;
}}return k;}
int longage2(char phe[ ]){
if (strlen(phe)==1||strlen(phe)%2!=0||phe[strlen(phe)]=='a'){
return 0;
}
for(int i=0;i<strlen(phe);i++){
if(i%2==0){
if(phe[i]!='a'){
return 0;
}}else{
if(phe[i]!='b'){
return 0;}}
}return 1;}

int longage3(char phe[]){
int a=occurrence(phe,'a');
if(occurrence(phe,'a')%2!=0){
return 0;}
else{
for(int i=0;i<occurrence(phe,'a');i++){
if(phe[i]!='a'){
return 0;
}}
if(occurrence(phe,'b')==0){
return 0;
}}
return 1;}
int longage4(char phe[]){
int a,k,j;char ph1[30];
if(phe[0]!='a'){ //||occurrence(phe,'a')<3 || occurrence(phe,'b')<2
return 0;
}else{

for( int i=0;i<=longer(phe,0)-1;i++){
ph1[i]=phe[i];
if(longage2(ph1)==1){
a=i;
}}
if(a<1){
return 0;
}
char ph2[a+2];
for(int j=0;j<=a;j++){
ph2[j]=ph1[j];
}
ph2[a+1]='\0';

//------------------------------------
char ph3[longer(phe,0)-(a+2)+1];
for (int o=a+1;o<=strlen(phe);o++){
ph3[k]=phe[o];
//printf("%d\n",longage3(ph3));
k=k+1;
}
ph3[strlen(ph3)+1]=='\0';
if(longage2(ph2)==1 &&longage3(ph3)==1){
return 1;
}else{ return 0;

}}}

int main()
{char phe[50];
printf("donnez un mot\n");
scanf("%s",phe);
if (longage4(phe)==1){
printf("Right");
}else{
printf("Wrong");}

return 0;
}

Answer 1

mar ia look at this :
Is this not correct one which are you looking?
//changes mentioned in comments.
https://code.sololearn.com/cnrr87I734Pf/?ref=app

Answer 2

mar ia

You have uninitialized variables access causing to code crash.. Assign values before using it.
In 1st function return i; instead return 0;
You are using == operator instead of '=' for assigning '\0'..
In loop conditions, use < only instead of <=

Instead writing code in description, copy to playground and share the link here.. That's helps to identify issue easily..

Pls Tag the language c instead c#.
Reply after modifications if still not work..

Answer 3

Thank you to everyone who contributed to finding a solution with me. I just want to tell you that I found the solution with your help. Thank you from the bottom of my heart.💛💛

Answer 4

mar ia please learn to do this:
Copy your code and go on your profile, then on "code bits", then click the "+" to create a new code.
Put there your code and save it, with any name you want. Don't forget to make it public!

Then come back here in the comments and click the "+" to insert a code. You'll find your code in your code bits.

After you added your code to the comment we can all help you in a better and easier way!

And the next times add the code directly in the question, instead of doing it in the comments.

Many thanks 🤗

Answer 5

https://code.sololearn.com/cgnI1yfmjJUk/?ref=app

Answer 6

I did it. Thanks for the help😊

Answer 7

Ab*n -->ab*2=aabb
ab^(2n)--> exp:n=1->ab^2=abab

Answer 8

The program works good ,but ther is bug
When i input (ababababaaaaaab)
The reasoult should be :abababab
aaaaaab
Right
But he didn't work
And in my pc he didnt work in the boocl i but comment in thes boocl
https://code.sololearn.com/c7koXSD6pq0I/?ref=app

Answer 9

I use code blocks 17.12 in my pc

Answer 10

Program work is
longage 2=Test the word if it belongs to ab^(2n).......n>1 exp:ab or abab or ababab ........
longage 3=Test the word if it belongs to a^(2n) b^(m)......m&n>1 exp:aab or aaaab ........
longage 4=looking for longage 2 and longage3 in the word With this rool (longage4=longage2.longage3).......exp(longage4=abaab-->longage2=ab+longage3=aab)

Answer 11

Jayakrishna🇮🇳 in 1st function i return 0 not i It's wrong

The 1st fonctin works well alone I have a problem whith the fanction nember 5

Answer 12

mar ia in line 71 you need "=" instead of "=="
And in line 59 you don't need the "int" inside the for. Write for( j=0...

If you make this changes to the code that you posted, then everyone will see the new corrected version.

The code is still not working, but we are doing progress 😅

Answer 13

There is no problem, I am still looking into the error, and I will try again until I find a solution💪💪

Answer 14

Program work is
longage 2=Test the word if it belongs to ab^(2n).......n>1 exp:ab or abab or ababab ........
longage 3=Test the word if it belongs to a^(2n) b^(m)......m&n>1 exp:aab or aaaab ........
longage 4=looking for longage 2 and longage3 in the word With this rool (longage4=longage2.longage3).......exp(longage4=abaab-->longage2=ab+longage3=aab)

For longage2:
ab or abab or ababab means ab*n
I don't know what ab^(2n) means.

For longage3 is the same:
aab or aaaab means a*n and then b

For longage4 I got that calls longage 2 and 3.

Anyway the only way you can make this program work is to add comments everywhere.
Write a comment for every line of code, explaining what is exactly doing.
You don't do it to make other people understand your code as much as you do it to make yourself understand what the code is actually doing.
If you do this (addin comments everywhere) you will probably find things to fix.
When you are done you either have a working program, or a non-working program that is easy to check.

Answer 15

how to input something

Answer 16

how to input something the input is abababaaaaaab

Answer 17

mar ia I think he speaks about input something in general, not in your code.
He is new and he thinks he's asking a question rather than commenting another question. So cute.

Anyway I am happy for you that you finally solved the problem! 🤗