Whats the logic of print the answer out?

Question

scores = [88,90,40,60,65,91,98]
a_score = filter(lambda i : True if i >= 90 else False, scores)
for k in a_score:
print(k)

Whyl it would result an error if directly print the "a_score" out, as well as need to use for..in loop to print it out?

Answer 1

a_score is not a list, so you cannot print it directly until a conversion. This is also mentioned in the lessons

https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2461/

Answer 2

It creates a filter object (like a generator) and not a list. Remember that such objects are iterable (but cannot be indexed). You need to make it into a list to print it out.
a_score = list(filter( ... ))

Answer 3

CarrieForle I see, I havent been there (the lesson)before. Thanks a lot!

Answer 4

Abhinav Anand Good! Thank you so much!