You are given a program that outputs all the numbers from 0 to 20. Change the code to make it output only numbers that are mult

Question

You are given a program that outputs all the numbers from 0 to 20.
Change the code to make it output only numbers that are multiples of 3. I want it's solution in C++.

Answer 1

Try this:

for(int num=0;num<=20;num++)
{
if(num%3==0)
{
cout<<num<<endl;
};
};

Answer 2

if (number%3==0):
cout<<number

just to tell you it's a hint(more of an actual solution) ,do not use Q&A for asking codes tho ,post what you have tried and format your question properly to ask if you have a certain doubt related about what you can't really understand

Answer 3

int num=0

While (num<20){
Cout << num;
num=(num+1)*3;
}

This is my attempt
But its out are 3 and 12
But the expected outs are 3,6,12

Answer 4

try this

#include <iostream>
using namespace std;

int main()
{
//change the code
int num = 0;
while(num<=20 ){
cout<<num<<endl;
num+=3;

if(num==0){
continue;
}

}

return 0;
}

Answer 5

Try This! CHEERS!!

#include <iostream>
using namespace std;

int main()
{

int num;
for(num=0;num<=20;num++)
{
if(num%3==0 && num!=0 )
{
cout<<num<<endl;
}
}

return 0;
}

Answer 6

try this ,its easy

while(number<=20 )
{
if(num%3==0 && number!=0)
cout<<number<<endl;
number+=3
}

Answer 7

int num = 0;
if(num +=3 ){
while ( num <= 20){
cout<<num<<endl;
num+=3;}
}

return 0;
}

Answer 8

#include <iostream>
using namespace std;

int main()
{
int num = 3;
while(num<=20){
cout<<num<<endl;
num+=3;

}

return 0;
}

Answer 9

#include <iostream>
using namespace std;

int main()
{
//change the code
int num = 3;
while(num<=20){
cout<<num<<endl;
num+=3;
}

return 0;
}

Answer 10

#include <iostream>
using namespace std;

int main()
{
//change the code
int num = 0;
while(num<=20){
if(num==0){
cout<<endl;
}
else{
cout<<num<<endl;
}
num=num+3;
}
return 0;
}

Good Luck

Answer 11

The provided code stores the value 7 in a variable, and outputs it.

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