How to fix this , I want the Result to be lowest to highest but the output is the opposite? And there's a error.

Question

#include <stdio.h>

int main()
{
int num, counter;
counter=0;

printf("Input a number between 0 to 50:");
scanf("%d",&num);

printf("\n");

if(num <= 50 && num >= 0)
while(0 <= num) {
printf("%d %d %d %d %d %d %d %d %d %d \n",num,num - 1,num - 2,num - 3,num - 4,num - 5,num - 6,num - 7,num - 8,num - 9);
num -= 10;
}
else
printf("\nInvalid Input");

return 0;
}
https://code.sololearn.com/cR7H37TIVbS4/?ref=app

Answer 1

This is the output when I inputted 20.

Input a number between 0 to 50: 20
20 19 18 17 16 15 14 13 12 11
10 9 8 7 6 5 4 3 2 1
0 -1 -2 -3 -4 -5 -6 -7 -8 -9

If you want the output to be like this, the code is below.
Input a number between 0 to 50:
0 -1 -2 -3 -4 -5 -6 -7 -8 -9
10 9 8 7 6 5 4 3 2 1
20 19 18 17 16 15 14 13 12 11

Replace your if-statement with this:
if(num <= 50 && num >= 0) {
counter = num;
num = 0;
while(num <= counter) {
printf("%d %d %d %d %d %d %d %d %d %d \n",num,num - 1,num - 2,num - 3,num - 4,num - 5,num - 6,num - 7,num - 8,num - 9);
num += 10;
}
} else
printf("\nInvalid Input");

Using the above code will also fix your warning about counter being unused because the code above actually uses counter. It isn't the best name for a variable used to just remember the original num value but it works.

If you just want to go from 0 to the inputted number with 10 values per line, I would add another loop through the 10 integers in each line instead of having so much similar code repeated for each of the 10.

Answer 2

There is a warning because you didn't used the "counter" variable.